Metric completion of the Bender--Brody--Müller Hamiltonian: dilation spectrum and missing eigenstates

• URL: http://arxiv.org/abs/2607.19067v1
• Date: Tue, 21 Jul 2026 12:58:24 GMT
• Title: Metric completion of the Bender--Brody--Müller Hamiltonian: dilation spectrum and missing eigenstates
• Abstract summary: Bender--Brody--Mller (BBM) Hamiltonian was proposed as a non-Hermitian Hilbert--Plya operator.<n>We analyze the Hilbert completion induced, on the standard half-line $L2$ core, by BBM's candidate metric.
• Score: 1.8867357521563244
• License: http://creativecommons.org/licenses/by/4.0/
• Abstract: The Bender--Brody--Müller (BBM) Hamiltonian was proposed as a non-Hermitian Hilbert--Pólya operator. We analyze the Hilbert completion induced, on the standard half-line $L^2$ core, by BBM's candidate metric $\hatη=\sin^2(\hat p/2)=Δ^\daggerΔ/4$. The form $η_0=Δ^\daggerΔ$ is positive with trivial kernel but is not coercive. Completing $C_c^\infty(0,\infty)$ in the norm $\|ψ\|_{η_0}=\|Δψ\|$ gives a Hilbert space canonically unitarily equivalent to $L^2(\mathbb R_+)$. Its free self-adjoint realization is the dilation generator, with simple, purely absolutely continuous spectrum $\mathbb R$. The analysis yields two spectral statements of interest beyond the BBM problem. First, no bounded sandwich $Δ^\dagger h(D)Δ$ is boundedly invertible. Second, the transported symmetric operator has deficiency indices $(\infty,\infty)$ and an adjoint with every real point as an eigenvalue of infinite multiplicity, while its free extension is purely continuous. The realization-independent BBM conclusion concerns the candidate eigenfunctions: $Δψ_z=x^{-z}$, so for $\operatorname{Re}z=1/2$ they do not belong to the completed space. Thus the original BBM boundary-condition/eigenfunction mechanism cannot produce point-spectrum Riemann-zero states in this $L^2$-based metric completion.

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