On the Complexity of Low-Rank Matrix Signing and Entrywise Power Matrix Factorization
- URL: http://arxiv.org/abs/2607.04875v2
- Date: Thu, 09 Jul 2026 20:42:41 GMT
- Title: On the Complexity of Low-Rank Matrix Signing and Entrywise Power Matrix Factorization
- Abstract summary: We show that entrywise power matrix factorization (EPMF) is NP-hard, already when $r=2$, the smallest non-trivial case.<n>EPMF is equivalent to the problem of flipping the signs of the entries of a given matrix $X$ to obtain a rank-$r$ matrix.
- Score: 9.842769671181276
- License: http://arxiv.org/licenses/nonexclusive-distrib/1.0/
- Abstract: Given a nonnegative matrix $X$, a factorization rank $r$ and {a positive integer $p$}, entrywise power matrix factorization (EPMF) looks for a low-rank matrix $X_r$ such that $X = |X_r|^{\circ p}$ (exact case) or $X \approx |X_r|^{\circ p}$ (approximate case), where $(\cdot)^{\circ p}$ denotes the componentwise exponent. EPMF includes the modulus model ($p=1$) and componentwise square factorization ($p=2$) as special cases, the latter being closely related to the square root rank. We analyze the computational complexity of the exact decision problem and the Frobenius-norm approximation problem, and establish a complete complexity landscape. In the exact case, we show that EPMF is equivalent to the combinatorial problem of flipping the signs of the entries of a given matrix $X$ to obtain a rank-$r$ matrix, which we refer to as the low-rank matrix signing (LRMS) problem. We first show that LRMS, and hence exact EPMF, is strongly NP-hard, improving a weak NP-hardness result for the square-root-rank (Math. Prog., 2015). We then show that LRMS can be solved in polynomial time when $r$ is fixed. Moreover, when the rank $r$ is part of the input, we show that for generic matrices the algorithm is fixed-parameter tractable (FPT) in the parameter $r$; in fact, the running time is fixed-parameter linear in the number of entries of the input matrix. In the approximate case using the Frobenius norm as an error measure, we show that EPMF is NP-hard, already when $r=2$, the smallest nontrivial case.
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